C89,调用函数指针,需要在函数指针前加*,对函数指针赋值,需要在函数名前面加&
C89,以后,对函数指针操作不需要& 和 *,但,使用它们是个好习惯
如下代码(C89函数指针风格)
#include <stdio.h>
#include <stdlib.h>
int max(int x, int y)
{
return (x > y ? x :y);
}
int main ( int argc, char *argv[] )
{
int (*p)(int,int) = &max; // 这里&max
int a, b, c;
scanf("%d%d", &a, &b);
c = (*p)(a,b); // 这里(*p)
printf("%d\n", c);
return EXIT_SUCCESS;
} Example
/* STRTOK.C: In this program, a loop uses strtok
* to print all the tokens (separated by commas
* or blanks) in the string named "string".
*/
#include <string.h>
#include <stdio.h>
char string[] = "A string/tof ,,tokens/nand some more tokens";
char seps[] = " ,/t/n";
char *token;
void main( void )
{
printf( "%s/n/nTokens:/n", string );
/* Establish string and get the first token: */
token = strtok( string, seps );
while( token != NULL )
{
/* While there are tokens in "string" */
printf( " %s/n", token );
/* Get next token: */
token = strtok( NULL, seps );
}
}#include <stdio.h>
int main()
{
char strBinary[sizeof(int)*8+1];
int a = 100;
// 让p指向strBinary的最后一位
char *p = strBinary + sizeof(int)*8;
*p = '/0';
while (a)
{
--p;
*p = (a & 1) + 0x30; // 加0x30转变成字符
a >>= 1; // 右移一位
}
printf("%s/n", p);
return 0;
}